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Intermediate Value Theorem
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Use the Intermediate Value Theorem to show that x^3-7x^2+14x-8=0 has at least one solution in the interval [0,5].Sketch the graph of y=x^3-7x^2+14x-8 over [0,5].How many solutions does this equation really have?
有谁可以教教我要怎样做? |
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发表于 17-10-2011 11:13 PM
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f(x)=x^3-7x^2+14x-8
f(0)<0
f(5)>0
by Intermediate Value Theorem
f(x) has root(s) in the interval [0,5]
f(x) = (x-4) (x-2) (x-1)
so 3 roots |
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